Quadratic Equations Model Questions Set 1 Practice Questions Answers Test With Solutions & More Shortcuts
QUADRATIC EQUATIONS PRACTICE TEST [1 - EXERCISES]
Quadratic Equations Model Questions Set 1
Question : 16
What are the roots of the equation $log_{10} (x^2 - 6x + 45)$ = 2?
a) 11, -5
b) -9, 5
c) -11,5
d) 9, -5
Answer »Answer: (a)
Given, $log_{10} (x^2 - 6x + 45) = 2$
⇒ $(x^2 - 6x + 45) = 10^2 = 100$
⇒ $x^2$ - 6x - 55 = 0
⇒ $x^2$ - 11x + 5x - 55 = 0
⇒ x(x - 11) + 5(x - 11) = 0
⇒ (x + 5) (x - 11) = 0
∴ x = 11, -5.
Question : 17
For what value of k, will the roots of the equation $kx^2$ - 5x + 6 = 0 be in the ratio of 2 : 3?
a) -1
b) 1
c) 2
d) 0
Answer »Answer: (b)
Let the roots of the equation be α and β
∴ α + β = $5/k$ and α β = $6/k$
Given, ${α}/{β} = 2/3$
⇒ α = $2/3$ β
∴ $2/3 β + β = 5/k and 2/3 β^2 = 6/k$
⇒ $5/3 β = 5/k and β^2 = 9/k$
β = $3/k and β^2 = 9/k$
⇒ $9/{k^2} = 9/k$
⇒ k = 1 and k ≠ 0. It is not satisfy the given condition.
Question : 18
If α and β are the roots of $ax^2$ + bx + c = 0, then what is the value of $(1/{α^2} - 1/{β^2})^2$
a) ${(b^2 - 4ac)}/{c^2}$
b) ${b (b^2 - 4ac)}/{c^2}$
c) ${(b^2 - 4ac)}/{c^4}$
d) ${b^2 (b^2 - 4ac)}/{c^4}$
Answer »Answer: (d)
α and β are the roots of the equation $ax^2$ + bx + c = 0
∴ α + β = - $b/a and α β = c/a$
∴ $(1/{α^2} - 1/{β^2})^2 = ({β^2 - α^2}/{α^2 β^2})^2$
= ${(α + β)^2 [(α + β)^2 - 4 α β]}/{(α^2 β^2)^2}$
= ${{b^2}/{a^2}({b^2}/{a^2} - {4c}/a)}/{({c^2}/{a^2})^2}$
= ${b^2}/{c^4} (b^2 - 4ac)$
Question : 19
What is one of the value of x in the equation $√{x/{1 - x}} + √{{1 - x}/x} = {13}/6$
a) $9/{13}$
b) $7/{13}$
c) ${11}/3$
d) $5/{13}$
Answer »Answer: (a)
Let $√{x/{1 - x}}$ = y
∴ $y + 1/y = {13}/6 ⇒ (y^2 + 1)6 = 13y$
⇒ $6y^2 - 13y + 6 = 0⇒6y^2 - 9y - 4y + 6 = 0$
⇒ 3y(2y - 3) -2(2y - 3) = 0
⇒ (3y - 2) (2y - 3) = 0
∴ $y = 2/3 and 3/2$
When, we put y = $2/3 ⇒ x/{1 - x} = 4/9$
⇒ 9x = 4 - 4x ⇒ x = $4/{13}$
When we put y = $3/2$
⇒ $x/{1 - x} = 9/4 ⇒ 4x = 9 - 9x$
∴ x = $9/{13}$
Question : 20
If the equations, $2x^2 - 7x + 3 = 0 and 4x^2$ + ax - 3 = 0 have a common root, then what is the value of a ?
a) 11 of - 4
b) - 11 0or - 4
c) 11 or 4
d) - 11 or 4
Answer »Answer: (d)
Given equation, $2x^2$ - 7x + 3 = 0
∴ $2x^2$ - 6x - x + 3 = 0
⇒ 2x(x - 3) - 1(x - 3) = 0
⇒ (2x - 1) (x - 3) = 0
Both equation have a common root.
So, we put x = $1/2 ⇒ 4(1/2)^2 + a(1/2)$ - 3 = 0
⇒ 1 + $a/2 - 3 = 0 ⇒ a/2$ = 2 ⇒ a = 4
Again, we put x = 3
$4(3)^2 + a(3) - 3 = 0$
⇒ 36 + 3a - 3 = 0 ⇒ a = - 11
a = - 11 or 4.
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